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(H)=70-4.9H^2
We move all terms to the left:
(H)-(70-4.9H^2)=0
We get rid of parentheses
4.9H^2+H-70=0
a = 4.9; b = 1; c = -70;
Δ = b2-4ac
Δ = 12-4·4.9·(-70)
Δ = 1373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1373}}{2*4.9}=\frac{-1-\sqrt{1373}}{9.8} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1373}}{2*4.9}=\frac{-1+\sqrt{1373}}{9.8} $
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